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In the molecule H2C=SF4 (methylenetetrafluorosulfane), which of the following statements about its geometry are correct? (S is the central atom with one double bond to C and four single bonds to F)

1. The two C-H bonds lie in the same plane as the axial S-F bonds
2. The two C-H bonds lie in the same plane as the equatorial S-F bonds
3. A total of six atoms are coplanar
4. The equatorial S-F plane is perpendicular to the plane of the pi bond

Correct answer: The two C-H bonds lie in the same plane as the equatorial S-F bonds

Solution

In H2C=SF4, S adopts a distorted octahedral environment (effectively trigonal bipyramidal counting the double bond as one direction). The C=S pi bond orients the H2C= group in the equatorial plane, making the C-H bonds coplanar with the equatorial S-F bonds.

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