Eight persons born in different years from 1951,1968,1993,1999,2001,2009 (base year 2020). Sum of ages of D and E = (H's age)². F born in leap year, not 1988. ≤3 persons born between years of C and F. D is eldest. Age and birth year of C are both odd. |age of E - age of F| = 4. Ages of A and B are multiples of 3. What is H's birth year?

1988
2001
2009
1972

Correct answer: 2009

Solution

Ages in 2020: 1951→69, 1968→52, 1993→27, 1999→21, 2001→19, 2009→11. D eldest → D=69. D+E = H²: 69+52=121=11² ✓. E=52(born 1968), H=11(born 2009). Answer: 2009.

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