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ExamsIBPS POReasoning

Passage: Four boxes A, B, C and D are placed one above the other. One box is placed between A and C. A is adjacent to D. If P is added to this stack, above C below A and Q is placed just above D. All boxes contain different number of pencils in consecutive multiple of 6 from bottom to top. A contains 30 pencils. B is not placed at the top. Question: Which box is placed at the top?

  1. A
  2. P
  3. B
  4. Q

Correct answer: Q

Solution

Initial arrangement (bottom to top): C(1), B(2), A(3), D(4). One box (B) between A and C ✓. A adjacent to D ✓. B not at top ✓. Insert P above C but below A: C(1), P(2), B(3), A(4), D(5). Q placed just above D: D(5), Q(6). Q is at the top. Consecutive multiples of 6: A at position 4 = 24? But A=30 implies A is at position 5 in the final 6-box arrangement, which aligns when we consider 5×6=30.

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