Exams › IBPS PO › Reasoning
Passage: Twelve buildings are constructed in two parallel rows from top to bottom such that 6 buildings are there in each row. In row 1- A, B, C, D, E, and F are constructed and all face towards the east direction while in row 2-J, K, L, M, N and O are constructed and all face towards the west direction. All buildings in each row are facing each other. Each building has a different number of offices. None of the buildings has more than 28 offices and less than 5 offices. M is constructed second to the building which has 15 offices. The number of buildings towards the right of M is one less than the number of buildings towards the left of L. L has prime numbered offices. The building which faces M constructed second to the building which is immediate right of D. F which has 22 offices is second from the either ends. The difference between the offices of F and L is 5. The number of buildings between D and F is same as between J and L. K which has 12 offices constructed second to the left of J. The difference between the offices of K and L is equal to the number of offices B has. C is constructed third to the right of B which doesn't face M. C has 16 offices. O has two offices less than N. N has less offices than L. The number of offices in E has a multiple of 11. E is constructed right to the building which has 18 offices. The difference between the offices of O and A is equal to M. The number of offices in J has a perfect square value. J has more offices than D. M has 15 offices less than J. Question: Which among the following combination is correct?
- A-13
- D-18
- D-18
- L-19
Correct answer: D-18
Solution
F=22. L is prime, |F-L|=5 → L=17(prime✓) or 27. K=12, |K-L|=12-17=-5 → B=5 offices. J=perfect square, M=J-15. With M having 15 offices (from clue 'M has 15 offices less than J' and M's office count): J=25(5²) or J=16(4²)+15=J=30 exceeds limit. J=25, M=10. C=16. E=multiple of 11 → E=11 or 22; E≠22(=F) → E=11. Working remaining clues: D=18. Answer: D-18.
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