Exams › IBPS PO › Reasoning
Passage: Eight people A, B, C, D, E, F, G, and H were born on the same date but in different years viz. 1972, 1980, 1958, 1960, 1968, 1988, 1999, and 1962. (Calculating all ages with respect to the year 2019) G was born eight years after B. A was born in an even number of years. Only one person was born in the odd number year whose age is multiple of 2. H is the youngest among all. C is not younger than A. The difference between the age of B and the person who was born in the year 1958 is 2 years. B is not older to the F whose age is 61. The age difference between D and E is 10 years older than the one who is four years younger than G. Question: Who is oldest among all?
- C
- D
- F
- B
Correct answer: F
Solution
Ages in 2019: born 1958→61, 1960→59, 1962→57, 1968→51, 1972→47, 1980→39, 1988→31, 1999→20. H=youngest=1999. F age=61 → F=1958. B not older than F → B≠1958. G=B+8: B=1960, G=1968 (only valid pair in the list). B-1958-person diff = |59-61|=2 ✓. H=1999(age20, odd year, 20=even multiple of 2 ✓). Remaining: A,C,D,E at 1962,1972,1980,1988 (all even years ✓). F=1958 is oldest (age 61).
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