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ExamsIBPS POReasoning

Seven persons A, B, C, D, E, F and G stand in a line facing north with different marks: 116, 130, 131, 136, 145, 150 and 180. What is A's position from the left and his marks? I. G is third to the right of the one with 145 marks (not at an extreme). C's marks are prime. $|E-D|=20$. B's marks are 5 less than E's. A is not the highest. The one with 150 marks sits immediately right of C. II. F is immediately left of B. The lowest marks are at the extreme left. D is not adjacent to G. A has more marks than F but fewer than G. The one with 150 marks is at the extreme right. E is not at the extreme left. D is adjacent to A, who is second to the left of C. D's marks are less than C's. Neither B nor D is adjacent to C. B is to the left of D but not at an extreme end. III. A has more marks than F but fewer than G. The one with 150 marks is at the extreme right. E is not at the extreme left. D is adjacent to A, who is second to the left of C. D's marks are less than C's. Neither B nor D is adjacent to C. B is to the left of D but not at an extreme end.

  1. All the statements are required
  2. Only I and II are sufficient
  3. Only II is sufficient
  4. Both I and III and II and III together are sufficient

Correct answer: Both I and III and II and III together are sufficient

Solution

Statement I alone is not enough to uniquely determine A. Statement II and Statement III each provide enough constraints when combined appropriately to determine A's position and marks. Hence, the sufficient combinations are II and III together, and I and III together, matching the given option.

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