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Toy C: Battery capacity = 120% of the battery capacity of Toy B. Battery percentage = 60%. NM/min = NM/min of Toy A + 5, HR/min = 30. At every 3rd NM and HR together, 1 unit of battery is consumed. What is the difference between the total NM and HR of Toy C when the battery of Toy C gets completely discharged? (Consider the available battery percentage.)

1. 1620
2. 1440
3. 1920
4. 1200

Correct answer: 1440

Solution

Toy C has 120% of Toy B’s capacity and only 60% charge available, so the usable battery is fixed accordingly. Using the given action rates and the rule that every 3rd combined NM and HR consumes 1 unit, the total combined count at discharge comes out to 1440.

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