Exams › IBPS PO › Quantitative Aptitude
Toy B: Battery capacity = 2000 units. Battery percentage = 75%. NM/min = 30, HR/min = 50% of the NM/min of Toy A. At every 3rd NM and HR together, 1 unit of battery is consumed. If Toy B and Toy A had been charged completely (100%), then what would be the difference between the time taken by both toys to get discharged completely?
- 50 min
- 90 min
- 15 min
- 0 min
Correct answer: 0 min
Solution
The question compares discharge times of two toys under the same consumption pattern. After accounting for the given rates and the 3rd-cycle battery consumption rule, both toys discharge in the same time when fully charged. Hence, the difference is 0 minutes.
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