Exams › IBPS PO › Quantitative Aptitude

I. x²-11x+24=0 II. y²+6y-135=0. Find relation.

1. x ≥ y
2. x < y
3. x ≤ y
4. x = y or Relation cannot be determined

Correct answer: x = y or Relation cannot be determined

Solution

I: (x-8)(x-3)=0→x=8 or 3. II: y²+6y-135=(y+15)(y-9)=0→y=-15 or 9. Pairs: (8,9): x<y; (8,-15): x>y; (3,9): x<y; (3,-15): x>y. Mixed results → relationship cannot be determined.

Related IBPS PO Quantitative Aptitude questions

• If (x^a)^c = x^c and \frac{x^{2b}}{x^a} = (x^{5a}) \times (x^d) \times (x^b), then compare Quantity I and Quantity II. Quantity I = b Quantity II = d
• Q83. If a > b for all integer values of a and b, then x = \frac{(a^2+ab)-(ab^2-b)}{2a^2b^2-ab} Compare: Quantity I: x Quantity II: 1.5
• Quantity I: \(\dfrac{(2a^3 + 2b^3)(a-b)}{(6a^2 - 7ab + 2b^2 + 5ab - 4a^2)(a^2 - b^2)}\) Quantity II: The value of P - 2Q if Q < -1 < P, where P and Q are integers.
• If $a-b=3$ and $a^2+b^2=29$, find the value of $ab$.
• The price of 2 sarees and 4 shirts is Rs. 1600. With the same money, one can buy 1 saree and 6 shirts. If one wants to buy 12 shirts, how much shall he have to pay?
• What should come in place of both $x$ in the equation $x = 162.128x$?

⚔️ Practice IBPS PO Quantitative Aptitude free + battle 1v1 →