Exams › IBPS PO › Quantitative Aptitude

B's still-water speed=A's+8. A-downstream:B-upstream=9:8. A-upstream:B-downstream=6:11. Compare: Q-I: Distance A covers downstream (125 min) + B covers upstream (75 min). Q-II: A,B,C upstream for 1 hr (C's still-water=50 km/h).

1. Quantity-I > Quantity-II
2. Quantity-I < Quantity-II
3. Quantity I ≤ Quantity II
4. Quantity-I = Quantity-II or No relation

Correct answer: Quantity-I > Quantity-II

Solution

Stream s=6, A_still=30, B_still=38. A_down=36, A_up=24, B_down=44, B_up=32. QI=36×125/60+32×75/60=75+40=115 km. QII=(24+32+44)×1=100 km. QI=115>QII=100.

Related IBPS PO Quantitative Aptitude questions

• Man rows at 6 km/hr in still water, stream = 2 km/hr. Time difference between upstream and downstream journey = 40 minutes. Find distance.
• Train A: 72 km/h. Train B: 3/4 × 72 = 54 km/h (same direction). A crosses B in 1 min 26 sec. Length of A = 25/18 × length of B. Find difference between lengths.
• QA: Train X=60km/h. Ratio X:Y=5:3 → Y=36km/h. Trains 100km apart, toward each other. Distance between them after 3 hours. QB: Bus=300m/12s=90km/h. Distance in 2 hours.
• Length of A + B = 410m. Speed_A:Speed_B = 4:7. Time to cross electric pole, A:B = 5:3. Find difference between length of B and A.
• Length_A = Length_B/2. Speed_A:Speed_B = 2:3. A crosses 100m platform in 5 seconds; B crosses 100m platform in 6 seconds. Find length of B.
• Trains A and B start simultaneously from X and Y towards each other. They cross after 4 hours. A takes 10 hours to travel XY. Find time for B to travel XY.

⚔️ Practice IBPS PO Quantitative Aptitude free + battle 1v1 →