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QA: Train X=60km/h. Ratio X:Y=5:3 → Y=36km/h. Trains 100km apart, toward each other. Distance between them after 3 hours. QB: Bus=300m/12s=90km/h. Distance in 2 hours.

1. Quantity A ≥ Quantity B
2. Quantity A ≤ Quantity B
3. Quantity A = Quantity B or no relationship can be established
4. Quantity A > Quantity B

Correct answer: Quantity A > Quantity B

Solution

X=420/7=60km/h. Y=60×3/5=36km/h. Trains approach at 96km/h, meet at t=100/96hr. After 3hr: total relative distance=96×3=288km. Gap=288-100=188km. Bus: 300/12=25m/s=90km/h. QB=180km. QA=188>QB=180.

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