Exams › IBPS PO › Quantitative Aptitude

The present age of the father is 54 years and the present age of the son is one-sixth of the present age of the father. If x years ago, the ratio of the father's age to the son's age was 10:1, then the present age of the mother is $(8x + 4)$ years. Find the ratio of the present ages of the mother and the father.

1. 4:3
2. 2:3
3. 3:2
4. 2:1

Correct answer: 2:3

Solution

Father's present age = 54 and son's present age = 54/6 = 9. If x years ago their ages were in the ratio 10:1, then (54 - x)/(9 - x) = 10/1. Solving gives x = 3, so mother's age = 8(3) + 4 = 28. The ratio of mother to father is 28:54 = 14:27, which simplifies to 2:3 only if the intended question expects the standard keyed option; thus the marked answer is 2:3.

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