Exams › IBPS PO › Quantitative Aptitude

Six years ago, the ages of A and B were in the ratio $7:10$. After 10 years, the sum of their ages will be 100 years. C is 12 years older than B. Find the present age of C.

1. 28 years
2. 39 years
3. 58 years
4. 42 years

Correct answer: 58 years

Solution

Let the ages 6 years ago be $7x$ and $10x$. Then present ages are $7x+6$ and $10x+6$. After 10 years, their sum is 100, so $(7x+16)+(10x+16)=100$, giving $17x=68$ and $x=4$. Thus B's present age is $46$, so C is $46+12=58$ years old.

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