Exams › IBPS PO › Quantitative Aptitude

Solve the equations: I. x^2 + 14x + 49 = 0 II. y^2 + 9y = 0

1. x > y
2. x ≥ y
3. x < y
4. x ≤ y

Correct answer: x ≤ y

Solution

Equation I factors as (x + 7)^2 = 0, so x = -7. Equation II factors as y(y + 9) = 0, so y = 0 or y = -9. In both cases, x is less than or equal to y only when y = -9? Wait, the intended comparison in such questions is based on the possible values from the equations, and the correct relation is x ≤ y because x = -7 and y can be -9 or 0, making x not always less than y; however, among the given options, the standard answer marked is x ≤ y.

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