Exams › IBPS PO › Quantitative Aptitude
Point Y is 10 m west of point G. Point U is 8 m north of O. Point G is 5 m north of point D. Point D is 10 m south of F. Point J is 4 m east of U. Point F is 6 m east of point J. If point M is 8 m north of point J, then what is the shortest distance of point M with respect to point F?
- 18 m
- 10 m
- 12 m
- 15 m
Correct answer: 10 m
Solution
Let $D=(0,0)$. Then $G=(0,5)$, $Y=(-10,5)$, and since $D$ is 10 m south of $F$, $F=(0,10)$. Also, $F$ is 6 m east of $J$, so $J=(-6,10)$. Since $M$ is 8 m north of $J$, $M=(-6,18)$. The distance between $M$ and $F$ is $\sqrt{(-6-0)^2+(18-10)^2}=\sqrt{36+64}=10$ m.
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