A can complete a work in 4 days, and B can complete it in 6 days. B started alone for one day, and then A joined him. Find the total time taken to complete the work.

2 days
3 days
8 days
12 days

Correct answer: 3 days

Solution

A’s one-day work = 1/4 and B’s one-day work = 1/6. B alone does 1/6 work in the first day, leaving 5/6. Together they work at 1/4 + 1/6 = 5/12 per day, so time for remaining work = (5/6) ÷ (5/12) = 2 days. Total time = 1 + 2 = 3 days.

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