Passage: Given data is regarding three automatic toys on two types of movements: Neck movements (NM) and Hand rotation (HR). It starts recording from 9 AM onwards on 12 June. Each toy has different battery percentage and battery capacity. Toy A: Battery capacity = 1500 units, battery perce

Question

Passage: Given data is regarding three automatic toys on two types of movements: Neck movements (NM) and Hand rotation (HR). It starts recording from 9 AM onwards on 12 June. Each toy has different battery percentage and battery capacity. Toy A: Battery capacity = 1500 units, battery percent = 80% At every 4th NM and 3rd HR together, 1 unit of battery is consumed. Toy A gets completely discharged at 11 AM. Toy B: Battery capacity = 2000 units, battery percent = 75% NM = 30/min, HR/min = 50% of NM/min of Toy A At every 3rd NM and 2nd HR together, 1 unit of battery is consumed. Toy C: Battery capacity = 120% of battery capacity of Toy B, battery percent = 60% NM/min = NM/min of Toy A + 5, HR = 30/min At every 3rd NM and 2nd HR together, 1 unit of battery is consumed. Question: Total number of NM/min of all the three toys together is what percent more than total number of HR/min of all the three toys together?

Accepted Answer

43.75%. The question asks for the total NM per minute and total HR per minute across all three toys. Once the individual rates are identified from the passage, the percentage by which NM exceeds HR is calculated using a0$(\text{NM}-\text{HR})/\text{HR} \times 100$. The result is 43.75%.

Solution

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