Exams › IBPS PO › Quantitative Aptitude
What is \(1397 \times 1397\)?
- 1951609
- 1981709
- 18362619
- 2031719
Correct answer: 1951609
Solution
Write \(1397 = 1400 - 3\). Then \((1400-3)^2 = 1400^2 - 2\cdot1400\cdot3 + 3^2 = 1960000 - 8400 + 9 = 1951609\).
Related IBPS PO Quantitative Aptitude questions
- If R scored his runs only in 6s and 4s and he hit 25 fours, then find the number of dot balls faced by R.
- In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
- A family consists of two grandparents, two parents, and three grandchildren. The average age of the grandparents is 67 years, that of the parents is 35 years, and that of the grandchildren is 6 years. What is the average age of the family?
- A grocer has sales of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230, and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?
- What is \(112 \times 54\)?
- If one-third of one-fourth of a number is 15, then three-tenths of that number is:
⚔️ Practice IBPS PO Quantitative Aptitude free + battle 1v1 →