Exams › IBPS PO › Quantitative Aptitude

Solve the following equations and compare the values of x and y: I. $2x^2 + 17x + 36 = 0$ II. $y^2 - 16 = 0$

1. if x > y
2. if x < y
3. if x ≥ y
4. if x ≤ y

Correct answer: if x ≤ y

Solution

Equation I factors as $(2x+9)(x+4)=0$, so $x=-\frac{9}{2}$ or $x=-4$. Equation II gives $y=\pm 4$. In every possible pairing, x is less than or equal to y, so the correct relation is x ≤ y.

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