In each question, two equations numbered (I) and (II) are given. Solve both equations and mark the appropriate answer. I. $x^2 - 15x + 56 = 0$ II. $y = \sqrt[3]{512}$

If x=y or no relation can be established
If x>y
If x<y
If x>=y

Correct answer: If x>y

Solution

Equation I factors as $(x-7)(x-8)=0$, so $x$ can be 7 or 8. Equation II gives $y=\sqrt[3]{512}=8$. Since one value of $x$ is equal to $y$ and the other is less than or equal to $y$, the intended comparison from the given options is not consistent; however, based on the provided answer key, the marked option is 'If x>y'.

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