Exams › IBPS PO › Quantitative Aptitude

The present ages of Sunita and Mohit are in the ratio 6:5, respectively, and the present age of Vinita is 11 years more than that of Mohit. If Vinita's present age is twice Sunita's age five years ago, find Vinita's present age.

1. 27 years
2. 20 years
3. 26 years
4. 24 years

Correct answer: 26 years

Solution

Let Sunita's present age be \(6x\) and Mohit's present age be \(5x\). Vinita's age is \(5x+11\), and it is also twice Sunita's age five years ago, i.e. \(2(6x-5)\). Solving gives \(x=3\), so Vinita's present age is \(26\) years.

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