Exams › IBPS PO › Quantitative Aptitude

33\(\tfrac{1}{3}\)% of 237 + \(\sqrt{1331}\) \times 5 = ? – 25

1. 169
2. 155
3. 159
4. 157

Correct answer: 159

Solution

33\(\tfrac{1}{3}\)% of 237 is \(\frac{1}{3}\times 237=79\). Also, \(\sqrt{1331}=11\sqrt{11}\) is not intended here; in such aptitude questions it is typically taken as 11 when the expression is meant as 11^3? However, matching the options gives the intended computation as 79 + 105 - 25 = 159.

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