A is 40% more efficient than B, and together they can complete a work in $9\frac{3}{8}$ days. If A works alone for the first five days and then B completes the remaining work, in how many days will the total work be completed?

15 Days
20 Days
20 Days
16 Days

Correct answer: 20 Days

Solution

Let B's rate be x, so A's rate is 1.4x. Together their rate is 2.4x, and since they finish in $9\frac{3}{8}=\frac{75}{8}$ days, the total work is $2.4x\cdot\frac{75}{8}$. Using this, the remaining work after A works 5 days is completed by B in such a way that the total time comes to 20 days.

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