Exams › IBPS PO › Quantitative Aptitude
Passage: Two series I and II are given below. Both series contain a wrong term, and both series follow different patterns. Solve the series and answer the question given below. Series I: a, b + 5, c + 8, 87, 412, 2185, 13326 Series II: b + 4, c + 8, 36, a + 50, 79, 111, 152 Note: (i) $10bx^2 - (21 - a)x + 3 = 0$, and the roots of the equation are $\frac{z}{10}$ and $\frac{y}{20}$, where $\frac{z}{10} > \frac{y}{20}$. (ii) Any multiple of $y$ gives a number with unit digit zero. (iii) $c - z = 9$ and $\mathrm{LCM}$ of $z$ and 5 is 15. If the wrong term of Series I is subtracted from 25, then what is the resultant term?
- 6
- 10
- 18
- 25
Correct answer: 18
Solution
Using the given conditions, the variables can be determined and the intended pattern of Series I becomes clear. The wrong term in Series I is 7, so subtracting it from 25 gives 18.
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