Exams › IBPS PO › Quantitative Aptitude
Given below is a series in which one number is wrong. Consider this wrong number as the value of A in the second series and find the value of D based on the pattern of the first series. 1, 3, 6, 21, 88, 445, 2676 (A), (B), (C), (D)
- 685
- 136
- 33
- 10
Correct answer: 136
Solution
The series follows a pattern where each term is obtained from the previous term by a specific operation, and one term breaks that pattern. Treating the wrong term as A in the second series allows the same pattern to continue. Applying the pattern gives D = 136.
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