Exams › IBPS PO › Quantitative Aptitude

Accepted and rejected applications from males are 5x and 3x respectively. Accepted and rejected applications from females are 5y and y respectively. If $5x + 5y = 725$ and $3x + y = 315$, then what is the number of rejected applications from males?

1. 200
2. 225
3. 240
4. 255

Correct answer: 255

Solution

From $5x+5y=725$, we get $x+y=145$. Also, $3x+y=315$. Subtracting the first from the second gives $2x=170$, so $x=85$. Rejected applications from males are $3x=255$.

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