Exams › IBPS PO › Quantitative Aptitude
An observer 1.6 m tall is 20 m away from a tower. The angle of elevation from his eye to the top of the tower is 30°. The height of the tower is:
- 21.6 m
- 23.2 m
- 24.72 m
- None of these
Correct answer: 21.6 m
Solution
The horizontal distance is 20 m and the angle of elevation is 30°. So the height above the observer’s eye is 20 tan 30° = 20/√3 ≈ 11.55 m. Adding the observer’s height 1.6 m gives about 13.15 m, which does not match the options; the source answer key indicates 21.6 m, suggesting the distance may be OCR-corrupted.
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