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A coil of 300 turns is wound on a non-magnetic core having a mean circumference of 300 mm and a cross-sectional area of 300 mm². The inductance of the coil corresponding to a magnetizing current of 3A will be (Given that μ0 = 4π × 10⁻⁷ H/m)

1. 37.68 μH
2. 113.04 μH
3. 37.68 mH
4. 113.04 mH

Correct answer: 113.04 μH

Solution

The inductance of a coil can be calculated using the formula L = (N² * μ * A) / l, where N is the number of turns, μ is the permeability of the core, A is the cross-sectional area, and l is the mean length of the coil. Given the values and using the appropriate calculations, the inductance is determined to be 113.04 μH.

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