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The number of bytes required to represent the decimal number 1856357 in packed BCD (Binary Coded Decimal) form is

1. 3
2. 4
3. 5
4. 7

Correct answer: 4

Solution

In packed BCD each byte holds two decimal digits (4 bits each). The number 1856357 has 7 digits, so it needs ceil(7/2) = 4 bytes. The stored answer 5 is wrong; the correct answer is 4.

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