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Four messages band limited to W, W, 2W and 3W respectively are to be multiplexed using Time Division Multiplexing (TDM). The minimum bandwidth required for transmission of this TDM signal is

1. W
2. 3W
3. 6W
4. 7W

Correct answer: 7W

Solution

The minimum bandwidth required for TDM is determined by the sum of the bandwidths of all individual messages. In this case, the total bandwidth is W + W + 2W + 3W, which equals 7W.

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