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The maximum reduction in cross-sectional area per pass, R, of a cold wire drawing process is R = 1 - e^{-(n+1)}, where n represents the strain-hardening coefficient. For a perfectly plastic material, R is

1. 0.865
2. 0.826
3. 0.777
4. 0.632

Correct answer: 0.632

Solution

A perfectly plastic material has strain-hardening coefficient n = 0. Substituting into R = 1 - e^{-(n+1)} gives R = 1 - e^{-1} ≈ 0.632.

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