A box contains 2 washers, 3 nuts, and 4 bolts. Items are drawn from the box at random one at a time without replacement. The probability of drawing 2 washers first, followed by 3 nuts, and subsequently the 4 bolts is

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Accepted Answer

1/1260. Since the items must appear in one specific order, multiply the probabilities of each required draw without replacement. The probability is $\frac{2}{9}\cdot\frac{1}{8}\cdot\frac{1}{7}\cdot\frac{3}{6}\cdot\frac{2}{5}\cdot\frac{4}{4}\cdot\frac{3}{3}\cdot\frac{2}{2}\cdot\frac{1}{1}=\frac{1}{1260}$.

A box contains 2 washers, 3 nuts, and 4 bolts. Items are drawn from the box at random one at a time without replacement. The probability of drawing 2 washers first, followed by 3 nuts, and subsequently the 4 bolts is

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