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A fair dice is tossed two times. The probability that the second toss results in a value that is higher than the first toss is

1. 2/36
2. 2/6
3. 5/12
4. 1/2

Correct answer: 5/12

Solution

Of 36 equally likely ordered pairs, 15 have the second value greater than the first (second>first symmetric with first>second, ties excluded). So the probability is 15/36 = 5/12, option C, not 1/2.

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