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An examination consists of two papers, Paper 1 and Paper 2. The probability of failing in Paper 1 is 0.3 and that in Paper 2 is 0.2. Given that a student has failed in Paper 2, the probability of failing in Paper 1 is 0.6. The probability of a student failing in both the papers is

1. 0.5
2. 0.18
3. 0.12
4. 0.06

Correct answer: 0.12

Solution

P(fail both)=P(F1|F2)*P(F2)=0.6*0.2=0.12. The stored 0.06 is incorrect; the answer is 0.12.

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