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X, Y, and Z are three points on a plane with \(XY = 11\) cm, \(YZ = 13\) cm, and \(XZ = 24\) cm. The number of circles passing through points X, Y, and Z is:
- 0
- 2
- 1
- 3
Correct answer: 0
Solution
Here \(XY + YZ = 11 + 13 = 24 = XZ\), so the three points are collinear. A circle cannot pass through three distinct collinear points, hence the number of circles is zero.
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