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ExamsSSC CGL (Prelims)Maths

X, Y, and Z are three points on a plane with \(XY = 11\) cm, \(YZ = 13\) cm, and \(XZ = 24\) cm. The number of circles passing through points X, Y, and Z is:

  1. 0
  2. 2
  3. 1
  4. 3

Correct answer: 0

Solution

Here \(XY + YZ = 11 + 13 = 24 = XZ\), so the three points are collinear. A circle cannot pass through three distinct collinear points, hence the number of circles is zero.

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