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A rectangular piece of paper is 50 cm long and 22 cm wide. If a cylinder is formed by rolling the paper along its breadth, then the volume of the cylinder is:

1. 2,125 cm³
2. 1,925 cm³
3. 2,025 cm³
4. 1,825 cm³

Correct answer: 1,925 cm³

Solution

If the paper is rolled along its breadth, the breadth 22 cm becomes the circumference of the base, so $2\pi r=22$. Thus $r=3.5$ cm and height $h=50$ cm. Volume is $\pi r^2 h = \frac{22}{7}\times 3.5^2 \times 50 = 1925$ cm³.

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