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ExamsSSC CGL (Prelims)Maths

If each side of an equilateral triangle is $37\sqrt{3}$ cm, then its altitude (in cm) is equal to:

  1. 37.5
  2. 18.5
  3. 60.5
  4. 55.5

Correct answer: 55.5

Solution

In an equilateral triangle, altitude = $\frac{\sqrt{3}}{2}a$. Substituting $a=37\sqrt{3}$ gives altitude $=\frac{\sqrt{3}}{2}\times 37\sqrt{3}=\frac{37\times 3}{2}=55.5$ cm.

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