Exams › SSC CGL (Prelims) › Maths

Express \(\sin 74^\circ + \tan 74^\circ\) in terms of trigonometric ratios of angles between \(0^\circ\) and \(45^\circ\).

1. sec 16° + cot 16°
2. cosec 16° + sec 16°
3. cosec 16° + cot 16°
4. cos 16° + cot 16°

Correct answer: cos 16° + cot 16°

Solution

Since \(74^\circ = 90^\circ - 16^\circ\), we have \(\sin 74^\circ = \cos 16^\circ\). Also, \(\tan 74^\circ = \cot 16^\circ\). Therefore the expression becomes \(\cos 16^\circ + \cot 16^\circ\).

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