Exams › SSC CGL (Prelims) › Maths

For what value of $t$ is $\sin^2 t$ half of $\tan t$?

1. 60°
2. 45°
3. 30°
4. 22.5°

Correct answer: 45°

Solution

We need $\sin^2 t = \frac{1}{2}\tan t$. Testing standard angles, at $t=45^\circ$, $\sin^2 45^\circ=\frac12$ and $\frac12\tan45^\circ=\frac12$, so the condition is satisfied. Hence the correct value is $45^\circ$.

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