Exams › SSC CGL (Prelims) › General
Correct answer: 2 \sqrt{21} cm
For a direct common tangent, the length between the points of contact is \(\sqrt{d^2-(r_1-r_2)^2}\). Here, \(d=10\), \(r_1=6\), and \(r_2=2\), so length = \(\sqrt{100-16}=\sqrt{84}=2\sqrt{21}\) cm.