Exams › SSC CGL (Prelims) › General
Correct answer: 32 cm
For a chord at distance 12 cm from the center in a circle of radius 20 cm, half the chord is \(\sqrt{20^2-12^2}=\sqrt{400-144}=16\) cm. Therefore the full chord length is \(2\times 16=32\) cm. Since equal chords are equidistant from the center, PQ has the same length.