Exams › SSC CGL (Prelims) › General
Correct answer: 15 cm
The radius to the point of tangency is perpendicular to the tangent, so the radius and tangent form a right triangle with the line from the external point to the centre. Using Pythagoras, tangent length = \(\sqrt{17^2-8^2}=\sqrt{289-64}=\sqrt{225}=15\) cm.