Exams › SSC CGL (Prelims) › General
The price of a product is decreased by \(x\%\) and then increased by \(x\%\). The final price becomes 10% less than the original. What is the value of \(x\) approximately?
- 31.6
- 33.6
- 30.6
- 39.6
Correct answer: 31.6
Solution
After a decrease of \(x\%\) and then an increase of \(x\%\), the net multiplier is \(1-\frac{x^2}{10000}\). Since the final price is 10% less, the multiplier is 0.9. Solving gives \(1-\frac{x^2}{10000}=0.9\), so \(x^2=1000\) and \(x\approx31.6\).
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