Exams › SSC CGL (Prelims) › General
A man reduces his speed from 20 km/h to 18 km/h. He takes 8 minutes more than the normal time. What is the distance traveled by him?
- 20 km
- 21 km
- 22 km
- 24 km
Correct answer: 24 km
Solution
Let the distance be \(d\) km. Then the extra time is \(\frac{d}{18}-\frac{d}{20}=\frac{8}{60}\) hours. Solving gives \(d=24\) km.
Related SSC CGL (Prelims) General questions
⚔️ Practice SSC CGL (Prelims) General free + battle 1v1 →