Exams › SSC CGL (Prelims) › General

If \(x=\sqrt{7}+3\), find the value of \(x^2-6\sqrt{7}\).

1. 14
2. 15
3. 16
4. 17

Correct answer: 16

Solution

Expanding \((\sqrt{7}+3)^2\) gives \(7+9+6\sqrt{7}=16+6\sqrt{7}\). Subtracting \(6\sqrt{7}\) leaves 16.

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