Exams › SSC CGL (Prelims) › General

If $t=\sqrt{6}+3$, find $t^2-6\sqrt{6}$.

1. 3
2. 5
3. 9
4. 15

Correct answer: 15

Solution

Expand $t^2=(\sqrt{6}+3)^2=6+9+6\sqrt{6}=15+6\sqrt{6}$. Subtracting $6\sqrt{6}$ leaves $15$.

Related SSC CGL (Prelims) General questions

• If $3x + 7 = 28$, find $x$.
• Simplify: \((15 + \sqrt{3}) + (15 - \sqrt{3}) - (1025 - 3)\)
• If \(m + \frac{1}{m} = 6\), find the value of \(m^2 + \frac{1}{m^2}\).
• If $7x + 5 = 61$, then $x = ?$
• Find the y-intercept of \(5x + 3y = 15\).
• Given \(x + \frac{1}{x} = 5\), find \(x^3 + \frac{1}{x^3}\).

⚔️ Practice SSC CGL (Prelims) General free + battle 1v1 →