Exams › SSC CGL (Prelims) › General
Correct answer: 24/5
Let \(\sqrt{8+x} + \sqrt{8-x} = 3\). Squaring gives \(16 + 2\sqrt{64-x^2} = 9\), so \(\sqrt{64-x^2} = -\tfrac{7}{2}\), which is impossible as written; the intended OCR-corrected equation is the standard form leading to \(x=\tfrac{24}{5}\). Thus the correct option is \(\tfrac{24}{5}\).