Exams › SSC CGL (Prelims) › General
If \(\sqrt{x}+\sqrt{y}=7\) and \(\sqrt{x}-\sqrt{y}=3\), what are the values of x and y?
- x=16, y=9
- x=49, y=16
- x=36, y=1
- x=25, y=4
Correct answer: x=25, y=4
Solution
Adding the equations gives \(2\sqrt{x}=10\), so \(\sqrt{x}=5\) and \(x=25\). Subtracting gives \(2\sqrt{y}=4\), so \(\sqrt{y}=2\) and \(y=4\).
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