Exams › SSC CGL (Prelims) › General
Correct answer: 3 + \sqrt 5
Write \(\sqrt{14+6\sqrt5}\) as \(\sqrt x + \sqrt y\). Then \(x+y=14\) and \(2\sqrt{xy}=6\sqrt5\), so \(xy=45\). The numbers are 9 and 5, giving \(\sqrt9+\sqrt5=3+\sqrt5\).
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